x^2-4.8x+3=0

Solution for x^2-4.8x+3=0 equation:

x^2-4.8x+3=0

a = 1; b = -4.8; c = +3;
Δ = b2-4ac
Δ = -4.82-4·1·3
Δ = 11.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{11.04}}{2*1}=\frac{4.8-\sqrt{11.04}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{11.04}}{2*1}=\frac{4.8+\sqrt{11.04}}{2}
$